CASE STUDY QUESTION 19-Class X-Maths

CASE STUDY QUESTION 19-Class X-Maths

In the below given layout, the design and measurements has been made such that area of two bedrooms and Kitchen together is 95 sq. m.

(i) The area of two bedrooms and kitchen are respectively equal to
(a) 5x, 5y (b) 10x, 5y
(c) 5x, 10y (c) x, y
Area of one bedroom = 5x sq.m
Area of two bedrooms = 10x sq.m
Area of kitchen = 5y sq. m

(ii) Find the length of the outer boundary of the layout.
(a) 27 m (b) 15 m (c) 50 m (d) 54 m
Length of outer boundary = 12 + 15 + 12 + 15 = 54 m

(iii) Find the area of each bedroom.
(a) 30 sq. m (b) 35 sq. m
(c) 65 sq. m (d) 42 sq. m

Area of two bedrooms = 10x sq.m
Area of kitchen = 5y sq. m
So, 10x + 5y = 95  2x + y = 19
Also, x + 2 + y = 15 x + y = 13

Solving 2x + y = 19 and x + y = 13,
we get x = 6 m and y = 7 m
Area of bedroom = 5 x 6 = 30 sq. m

(iv) Find the area of living room in the layout.
(a) 30 sq. m (b) 35 sq. m
(c) 75 sq. m (d) 65 sq. m
Area of living room = (15 x 7) – 30
= 105 – 30 =75 sq. m

(v) Find the cost of laying tiles in Kitchen at the rate of Rs. 50 per sq. m
(a) Rs. 1500 (b) Rs. 2000 (c) Rs. 1750 (d) Rs. 3000
Cost of 1m2
laying tiles in kitchen = Rs. 50
Total cost of laying tiles in kitchen = Rs. 50 x 35 = Rs. 1750

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