# CASE STUDY QUESTION 19-Class X-Maths

CASE STUDY QUESTION 19-Class X-Maths

**In the below given layout, the design and measurements has been made such that area of two bedrooms and Kitchen together is 95 sq. m.**

**(i) The area of two bedrooms and kitchen are respectively equal to**

(a) 5x, 5y (b) 10x, 5y

(c) 5x, 10y (c) x, y

Area of one bedroom = 5x sq.m

Area of two bedrooms = 10x sq.m

Area of kitchen = 5y sq. m

**(ii) Find the length of the outer boundary of the layout.**

(a) 27 m (b) 15 m (c) 50 m (d) 54 m

Length of outer boundary = 12 + 15 + 12 + 15 = 54 m

**(iii) Find the area of each bedroom.**

(a) 30 sq. m (b) 35 sq. m

(c) 65 sq. m (d) 42 sq. m

Area of two bedrooms = 10x sq.m

Area of kitchen = 5y sq. m

So, 10x + 5y = 95 2x + y = 19

Also, x + 2 + y = 15 x + y = 13

Solving 2x + y = 19 and x + y = 13,

we get x = 6 m and y = 7 m

Area of bedroom = 5 x 6 = 30 sq. m

**(iv) Find the area of living room in the layout.**

(a) 30 sq. m (b) 35 sq. m

(c) 75 sq. m (d) 65 sq. m

Area of living room = (15 x 7) – 30

= 105 – 30 =75 sq. m

**(v) Find the cost of laying tiles in Kitchen at the rate of Rs. 50 per sq. m**

(a) Rs. 1500 (b) Rs. 2000 (c) Rs. 1750 (d) Rs. 3000

Cost of 1m^{2}

laying tiles in kitchen = Rs. 50

Total cost of laying tiles in kitchen = Rs. 50 x 35 = Rs. 1750